[dzach] 2005-Sept-29: An interesting article about a new book, '''DIVINE PROPORTIONS: Rational Trigonometry to Universal Geometry''', by N J Wildberger, appeared recently in [http://science.slashdot.org/article.pl?sid=05/09/17/1313249&threshold=5]. Here [http://en.wikipedia.org/wiki/Rational_trigonometry] is the wikipedia reference to the subject. In the sample chapter available for review [http://web.maths.unsw.edu.au/~norman/papers/Chapter1.pdf] the author gives a definition of the terms ''spread'' and ''quadrance''. In simple words, the ''spread'' is an expression of the separation of two lines ( spread = (sin(angle))**2 ) which "replaces" the angle of classic trigonometry in rational trigonometric calculations, while the ''quadrance'' is the square of a distance. Mathematically inclined minds may add more useful applications in this page. Here is a first take on how to find the ''spread'' between two lines, using tcl. ====== # Find the spread based on the coordinates of three points P0, P1, P2, which define lines |P0,P1| and |P0,P2| # # P1 # / # / # /| # / | # P0/ | # \ | spread S0 # \ | # \| # \ # \ # P2 # # use point coordinates to find quadrance proc Qc {x1 y1 x2 y2} { return [expr {pow($x2-$x1,2)+pow($y2-$y1,2)}] } # # use side length to find quadrance proc Qs sd { return [expr {pow($sd,2)}] } # find spread given coordinates proc Sc {x0 y0 x1 y1 x2 y2} { # find the quadrances of each side of triangle P0-P1-P2 formed by the points P0,P1,P2 set q0 [Qc $x2 $y2 $x1 $y1] set q1 [Qc $x0 $y0 $x1 $y1] set q2 [Qc $x0 $y0 $x2 $y2] # use the Cross law to find S0 return [expr {1-pow($q1+$q2-$q0,2)/(4.0*$q1*$q2)}] } # # find spread given sides proc Ss {sd1 sd2 sd3} { set q1 [Qs $sd1] set q2 [Qs $sd2] set q3 [Qs $sd3] # use the Cross law to find S1 set res [expr {1-pow($q2+$q3-$q1,2)/(4.0*$q2*$q3)}] if {$res>=0 && $res <=1.0} { return $res } else { error "This triangle cannot exist!" } } ====== '''Examples:''' Assume three points P0(0,0), P1(5,0) and P2(10,10), which define a horizontal line |P0,P1| and a slanted line |P0,P2|. The angle between the two lines is 45deg . The spread S0 will be: % Sc 0 0 5 0 10 10 0.5 Other examples: % Sc 0 0 50 0 100 75 0.36 % Sc 0 0 5 0 10 20 0.8 Assuming a triangle with sides 4, 5 and 6 units, find the spread opposite to side measuring 4 units (part of an example appearing in the sample chapter of the book mentioned above): % Ss 4 5 6 0.4375 Assuming a triangle with sides 3, 4 and 5 units, find the spread opposite to side measuring 4 units: % Ss 3 4 5 0.36 and for the other sides: % Ss 4 5 3 0.64 % Ss 5 3 4 1.0 This last one says that the spread opposite to side 5 corresponds to a right angle. More on this subject as soon as the book arrives and is read :-). <> Mathematics | Book